怎么解(2cos10°－sin20°)÷sin70°,
问题描述：
怎么解(2cos10°－sin20°)÷sin70°,
答
原式= (2cos10°-sin20°)/sin70°
=(2cos10°-sin20°)/cos20°
=[cos10°+(cos10°-cos70°)]/cos20°
=[cos10°+2sin40°*sin30°]/cos20°
=[cos10°+2*1/2*sin40°]/cos20°
=[cos10°+cos50°]/cos20 °
=2cos30°*cos20°/cos20°
=2cos30°
= 根号3