函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?
问题描述:
函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?
答
y=cos^2(x/4)-sin^2(x/4)
=cos[2*(x/4)]
=cos(x/2)
所以T=2π/(1/2)==4π