sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3 - x)
问题描述:
sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3 - x)
化简、、、
答
原式=sinxcosπ/3+cosxsinπ/3+2sinxcosπ/3-2cosxsinπ/3-√3cosxcos2π/3-√3sinxsin2π/3
=1/2*sinx+√3/2*cosx+sinx-√3cosx+√3/2*cosx-3/2*sinx
=0