若x∈(0,90°),化简(根号1-sinx)/2
问题描述：
若x∈(0,90°),化简(根号1-sinx)/2
答
1－sinx=[sin(x/2)]^2+[cos(x/2)]^2-2sin(x/2)cos(x/2)=[sin(x/2)-cos(x/2)]^2
若x∈(0,90°),化简(根号1-sinx)/2
1－sinx=[sin(x/2)]^2+[cos(x/2)]^2-2sin(x/2)cos(x/2)=[sin(x/2)-cos(x/2)]^2