计算(-3分之1xy²)²×[xy(2x-y)+xy²]=

问题描述:

计算(-3分之1xy²)²×[xy(2x-y)+xy²]=

(-3分之1xy²)²×[xy(2x-y)+xy²]
=1/9x²y的4次方 x(2x²y-xy²+xy²)
=1/9x²y的4次方 x2x²y
=2/9x的4次方y的5次方