y=ln(1-x^2),则y’= ,y'丨(x=0) =
问题描述:
y=ln(1-x^2),则y’= ,y'丨(x=0) =
答
y'=1/(1-x²)*(1-x²)'
=1/(1-x²)*(-2x)
=2x/(x²-1)
所以y'|(x=0)=0