sin²30°+cos²30°+√8tan45°-6sin45°+﹙-1﹚²º¹²
问题描述:
sin²30°+cos²30°+√8tan45°-6sin45°+﹙-1﹚²º¹²
答
sin²30°+cos²30°+√8tan45°-6sin45°+﹙-1﹚²º¹²=(sin²30°+cos²30°)+√8tan45°-6sin45°+﹙-1﹚²º¹²=1+2√2*1-6*√2/2+1=1+2√2-3√2+1=2...