(√48+4分之1+√6)除以√27

问题描述:

(√48+4分之1+√6)除以√27

(√48+4分之1+√6)除以√27
=√(48/27)+1/(4√27)+√(6/27)
=√(16/9)+1/(12√3)+√(2/9)
=4/3+√3/36+√2/3