求根号下(1-x^2)*x的不定积分
问题描述:
求根号下(1-x^2)*x的不定积分
答
原式=(1/2)∫√(1-x^2)d(x^2)
=-(1/2)∫√(1-x^2)d(1-x^2)
=-(1/2)×(2/3)(1-x^2)^(3/2)+C
=-(1/3)(1-x^2)√(1-x^2)+C