比较sin(-879),tan(-33π/8),cos(-13π/10)的大小,详细过程
问题描述:
比较sin(-879),tan(-33π/8),cos(-13π/10)的大小,详细过程
答
...运用周期①sin(-879)=sin(-879+360*3)=sin201=sin(180+21)=-sin21②tan(-33π/8)=tan(-33π/8+4π)=tan(-1/8π)③cos(-13π/10)=cos(-13π/10+2π)=cos(7/10π)=cos(π-3/10π)=-cos(3/10π)=-cos(54)=-cos(90-36...