tan(α+π/6)=3,则tan(α+5π/12)等于?

问题描述:

tan(α+π/6)=3,则tan(α+5π/12)等于?

tan(α+5π/12)
=tan[(α+π/6)+π/4]
=[tan(α+π/6)+tan(π/4)]/[1-tan(α+π/6)tan(π/4)]
=(3+1)/(1-3)
=4/(-2)
=-2