若5x^2-7xy-6y^2=0,求5x/3y的值
问题描述:
若5x^2-7xy-6y^2=0,求5x/3y的值
答
5x^2-7xy-6y^2=0
[十字相乘]
(5x+3y)(x-2y)=0
5x=-3y 或 x=2y
5x=-3y时
5x/3y=-3y/3y=-1
x=2y时
5x/3y=10y/3y=10/3