函数y=2sin(-2x+π/3)的相位和初相分别是什么?
问题描述:
函数y=2sin(-2x+π/3)的相位和初相分别是什么?
变形得y=2sin(2x+2π/3)所以相位是2x+2π/3,初相是2π/3.
是怎么变形的
答
解函数y=2sin(-2x+π/3)
=-2sin(2x-π/3)
=-[-2sin(π+2x-π/3)]
=-[-2sin(2x+2π/3)]
=2sin(2x+2π/3)