(a-4)(a-2)-(a-1)(a-3),其中a=-2分之5,先化简,在求值

问题描述:

(a-4)(a-2)-(a-1)(a-3),其中a=-2分之5,先化简,在求值

原式=(a²-6a+8)-(a²-4a+3)
=a²-6a+8-a²+4a-3
=-2a+5
=-2×(-5/2)+5
=5+5
=10