1.分解因式:b²-(a-b+c)²= y的四次方-1= 要用平方差公式,要过程

问题描述:

1.分解因式:b²-(a-b+c)²= y的四次方-1= 要用平方差公式,要过程

b²-(a-b+c)²=
=(b-a+b-c)(b+a-b+c)
=(2b-a-c)(a+c)
y的四次方-1=
=y^4-1²
=(y²-1)(y²+1)
=(y+1)(y-1)(y²+1)请问(x+y)(x-y)=2(x-y)=(x+y)²-9x²=(x+y)(x-y)-2(x-y)=(x-y)(x+y-2)(x+y)²-9x²=(x+y)²-(3x)²=(x+y-3x)(x+y+3x)=(y-2x)(4x+4)