根号下24-(根号下1/2+2根号下2/3)-根号下1/8-根号下6)【过程】
问题描述:
根号下24-(根号下1/2+2根号下2/3)-根号下1/8-根号下6)【过程】
答
√24 - (√1/2 + 2√2/3) - (√1/8 - √6) = 2√6 - [(√2)/2 + (2/3)√6] - [(√2)/4 - √6] = 2√6 - (√2)/2 - (2/3)√6 - (√2)/4 + √6 = (2 - 2/3 + 1) * √6 - (√2)/4 = (2√6)/3 - (√2)/4...