(8-4x)/(x^2+3x)+(2x-3)/(x+3)=2
问题描述：
(8-4x)/(x^2+3x)+(2x-3)/(x+3)=2
解分式方程
答
(8-4x)/(x^2+3x)+(2x-3)/(x+3)=2
(8-4x)/x(x+3)+(2x-3)/(x+3)=2
两边同乘以x(x+3)
8-4x+2x^2-3x=2x^2+6x
-13x=-8
x=8/13