计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy

分类: 作业答案 • 2021-12-18 22:42:11

问题描述：

答

[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
=（9x²-12xy+4y²-9x²-12xy-4y²+3x²y²）÷2xy
=-21xy÷2xy
=-10.5

答

[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
=(9x²-12xy+4y²-9x²-12xy-4y²+3x²y²)÷2xy
=(-24xy+3x²y²)÷2xy
=-12+3xy/2

答

原式=（9x^2-12xy+4y^2-9x^2-12xy-4y^2+3x^2y^2)/2xy
=(-24xy+3x^2y^2)/2xy
=-12+3/2*xy