已知x+y=1,xy=3/16,求x³y-2x²y²+xy³

分类: 作业答案 • 2021-12-18 22:43:35

问题描述：

答

x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy[(x+y)²-4xy]
=3/16*(1²-4*3/16)
=3/64