计算x²+4/x+3+x²-x-6/x+3-2x²-2x-5/x+3=
问题描述:
计算x²+4/x+3+x²-x-6/x+3-2x²-2x-5/x+3=
答
x²+4/x+3+x²-x-6/x+3-2x²-2x-5/x+3
=(x²+4+x²-x-6-2x²-2x-5)/(x+3)
=(-3x-7)/(x+3)
=-(3x+7)/(x+3)