x2+4xy+y2+x2y2+1=0,求x,y的值.

问题描述:

x2+4xy+y2+x2y2+1=0,求x,y的值.

∵x2+4xy+y2+x2y2+1=0,
∴x2+2xy+y2+x2y2+2xy+1=0,
∴(x+y)2+(xy+1)2=0,
∴x+y=0,xy+1=0,
∴x=1,y=-1或x=-1,y=1.