cosα+sinα=√6/2(0<α<π/4)则α=
问题描述:
cosα+sinα=√6/2(0<α<π/4)则α=
答
cosα+sinα=√6/2
√2*cos(α-π/4)=√6/2
cos(α-π/4)=√3/2
α-π/4=kπ+π/6
α=kπ-π/12 k∈z
答
cosα+sinα=√6/2
√2sin(α+π/4)=√6/2
sin(α+π/4)=√3/2(0<α<π/4)
α=π/12