(2+1)(2²+1)(2∧4+1)(2∧8+1)
问题描述：
(2+1)(2²+1)(2∧4+1)(2∧8+1)
答
原式=
(2-1)(2+1)(2²+1)(2^4 + 1)(2^8 +1)
=(2² -1)(2²+1)(2^4 + 1)(2^8 +1)
=(2^4 - 1)(2^4 + 1)(2^8 +1)
=(2^8 -1)(2^8 +1)
=(2^16 -1)
=65535