(2x-7)²-(x+1)²=0 (x-6)²-25=0用因式分解法怎么解
问题描述:
(2x-7)²-(x+1)²=0 (x-6)²-25=0用因式分解法怎么解
答
解(2x-7)²-(x+1)²=0[(2x-7)+(x+1)][(2x-7)-(x+1)]=0(3x-6)(x-8)=0∴x=2或x=8解(x-6)²-25=0(x-6)²-5²=0(x-6+5)(x-6-5)=0(x-1)(x-11)=0x=1或x=11