若π<x<3π/2,则sqrt(tanx+sinx)+sqrt(tanx-sinx)=?

问题描述:

若π<x<3π/2,则sqrt(tanx+sinx)+sqrt(tanx-sinx)=?
A.2·sqrt(tanx)·sin(x/2-π/4) B.2·sqrt(tanx)·sin(x/2+π/4)
C.-2·sqrt(tanx)·sin(x/2-π/4) D.-2sqrt(tanx)`·sin(x/2+π/4)
sqrt根号

A π<x<3π/2 π/2<x/2<3π/4 sinx