已知cos(π/6+θ)=根号3/3,求cos(5π/6-θ)的值

问题描述:

已知cos(π/6+θ)=根号3/3,求cos(5π/6-θ)的值

cos(π/6+θ)=cos(-(π/6+θ))=-cos(-(π/6+θ)+π)=-cos(5π/6-θ)
所以:
cos(5π/6-θ)=-cos(π/6+θ)=-根号3/3.