点A(a,a+1)在函数y=-2x-6的图象上,则a=_.
问题描述:
点A(a,a+1)在函数y=-2x-6的图象上,则a=______.
答
根据题意,得
a+1=-2a-6,
解得a=-
;7 3
故答案是:-
.7 3