复数计算
问题描述：
复数计算
（√3i-1)^10+(-√3i-1)^10
答
原式=[2^10(-1/2+√3i/2）^10]+2^10[(1/2+√3i/2）^10]=2^10[cos(2π/3）+isin(2π/3)]^10+2^10[cos(π/3）+isin(π/3)]^10=1024[cos(20π/3）+isin(20π/3)]+1024[cos(10π/3）+isin(10π/3)]=1024[cos(2π/3）+isi...