若s=vt-1/2gt^2,求在t=1,t=1+△t之间的平均速度,其中△t=1,0.1,0.01
问题描述:
若s=vt-1/2gt^2,求在t=1,t=1+△t之间的平均速度,其中△t=1,0.1,0.01
答
△S=v(t+△t)-1/2g(t+△t)^2-vt-1/2gt^2=v△t-gt△t-1/2g△t△S/△t=v-gt-1/2g△t△t=1,△S/△t=v-gt-1/2g△t=0.1,△S/△t=v-gt-1/20g△t=0.1,△S/△t=v-gt-1/200g