先化简,再求值:y(x+y)+(x+y)(x-y)-x2,其中x=-2,y=1/2.

问题描述:

先化简,再求值:y(x+y)+(x+y)(x-y)-x2,其中x=-2,y=

1
2

y(x+y)+(x+y)(x-y)-x2
=xy+y2+x2-y2-x2
=xy,
当x=-2,y=

1
2
时,原式=-2×
1
2
=-1.