已知×=负二分之一y=负三分之一z=六分之一求19(x-y+z)的平方减﹣24(x-y-z﹚减112﹙x-y+z﹚的值

问题描述:

已知×=负二分之一y=负三分之一z=六分之一求19(x-y+z)的平方减﹣24(x-y-z﹚减112﹙x-y+z﹚的值

19(x-y+z)²-24(x-y-z)-112(x-y+z)
=19(-1/2+1/3+1/6)²-24(-1/2+1/3-1/6)-112(-1/2+1/3+1/6)
=19×0²-24×(-1/3)-112×0
=8