(x²-4x+4分之x²-4+x+2分之2-x)除以x-2分之x

问题描述:

(x²-4x+4分之x²-4+x+2分之2-x)除以x-2分之x

(x2-4x+ x2/4-4+x+(2-x)/2)/(x/x-2)=(5/4x2-3x-4+(2-x)/2)/(x/x-2)=1/4(5x2-12x-16+4-2x)/(x/x-2)=(5x2-14x-12)(x-2)/4x (x2-4x+ 1/4(x2-4)+x+(2-x)/2)/(x/x-2)=1/4(5x2-14x-4)/(x/x-2)=(5x2-14...