(1-sin^4a-cos^4)/(sin^2a-sin^4a) 化简
问题描述:
(1-sin^4a-cos^4)/(sin^2a-sin^4a) 化简
答
(1-sin^4a-cos^4)/(sin^2a-sin^4a)
={1-[(sina)^2+(cosa)^2]^2+2(sina)^2*(cosa)^2}/{(sina)^2*[1-(sina)^2]}
=[2(sina)^2*(cosa)^2]/[(sina)^2*(cosa)^2]
=2