(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?
问题描述：
(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?
[x+1-(1-x)分之1]除以[x-(x-1)分之x^2]等于几?
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答
(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?
=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)
=(x²-x-6+x-3)/x(x-3)
=(x²-9)/x(x-3)
=(x+3)/x
[x+1-(1-x)分之1]除以[x-(x-1)分之x^2]等于几?
=[(x+1)+1/(x-1)] ×(x-1)/(-x)
=x²/(x-1) ×(x-1)/(-x)
=-x