limx趋向于无穷(1/(√x∧2+1)+1/(√x∧2+2)+.+1/(√x∧2+x))用夹逼准则证明等于1
问题描述:
limx趋向于无穷(1/(√x∧2+1)+1/(√x∧2+2)+.+1/(√x∧2+x))用夹逼准则证明等于1
答
x/(√x^2+x)
limx趋向于无穷(1/(√x∧2+1)+1/(√x∧2+2)+.+1/(√x∧2+x))用夹逼准则证明等于1
x/(√x^2+x)