(2根号2+3)^2005次方乘以(2根号2-3)^2006次方
问题描述：
(2根号2+3)^2005次方乘以(2根号2-3)^2006次方
答
(2根号2+3)^2005次方乘以(2根号2-3)^2006次方= (2根号2+3)^2005次方乘以(2根号2-3)^2005次方再乘以(2根号2-3)^1=【（2根号2+3）乘以(2根号2-3)】^2005乘以(2根号2-3)^1=[（2根号2）^2-3^2]^2005乘以(2根号2-3)=【8-9】^2005乘以(2根号2-3)=（-1）^2005乘以(2根号2-3)=-1乘以(2根号2-3)=3-2根号2
答
(2根号2+3)^2005次方乘以(2根号2-3)^2006次方
=(2根号2+3)^2005次方乘以(2根号2-3)^2005次方×(2√2-3)
=[(2根号2+3)乘以(2根号2-3)]^2005次方×(2√2-3)
=[8-9]^2005次方×(2√2-3)
=3-2√2