tanα=2则tan(α-π/6)=5根号3-8,

问题描述:

tanα=2则tan(α-π/6)=5根号3-8,

tanα=2,tanπ/6=√3/3
所以tan(α-π/6)
=(tanα-tanπ/6)/(1+tanαtanπ/6)
=5√3-8