∫1/[x^2(x^2+1)]dx的不定积分怎么算
问题描述:
∫1/[x^2(x^2+1)]dx的不定积分怎么算
答
∫dx/[x^2(x^2+1)]
=∫[1/x^2 -1/(x^2+1)] dx
= -1/x - arctanx + C