化简求值:(x+1)(x2+1)(x4+1)(x8+1)其中x=2
问题描述:
化简求值:(x+1)(x2+1)(x4+1)(x8+1)其中x=2
答
:(x+1)(x^2+1)(x^4+1)(x^8+1)其中x=2 (x-1)=1:(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)=(x^2-1))(x^2+1)(x^4+1)(x^8+1)=(x^4-1))(x^4+1)(x^8+1)=(x^8-1)(x^8+1)=x^16-1=2^16-1...