十字相乘法分解因式(a²+2a+3)²-13(a²+2a+3)+22

分类: 作业答案 • 2022-01-09 18:04:45

问题描述：

答

1 -2
1 -11
所以 (a²+2a+3)²-13(a²+2a+3)+22
=(a²+2a+3-2)(a²+2a+3-11)
=(a²+2a+1)(a²+2a-8)
1 1 1 4
1 1 1 -2
所以 (a²+2a+3)²-13(a²+2a+3)+22
=(a+1)²(a+4)(a-2)