y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
问题描述:
y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
答
2x√(1-x2) ≤ x2+1-x2 来源于
{x - √(1-x2)}^2 ≥ 0
x^2 - 2x√(1-x2) + (1-x2) ≥ 0
x^2 + (1-x2) ≥ 2x√(1-x2)