若x2-2x+y2+6y+10=0,求x,y的值
问题描述:
若x2-2x+y2+6y+10=0,求x,y的值
答
x2-2x+y2+6y+10=0
x^2-2x+1+y^2+6x+9=0
(X-1)^2+(Y+3)^2=0
则x-1=0
y+3=0
所以x=1,y=-3