(2x-3y)^2-(2x+3y)(2x-3y)因式分解（m+n)^2-4(m-n)^26x^2y(x-y)-2xy^2(x-y)+8xy(y-x)(x-y)^2-xy^2+X^2y
问题描述：
(2x-3y)^2-(2x+3y)(2x-3y)因式分解
（m+n)^2-4(m-n)^2
6x^2y(x-y)-2xy^2(x-y)+8xy(y-x)
(x-y)^2-xy^2+X^2y
答
(2x-3y)^2-(2x+3y)(2x-3y)
=(2x-3y)(2x-3y-2x-3y)
=-6y(2x-3y)
（m+n)^2-4(m-n)^2
=(m+n)^2-[2(m-n)]^2
=[(m+n)-2(m-n)][(m+n)+2(m-n)]
=(3n-m)(3m-n)
6x^2y(x-y)-2xy^2(x-y)+8xy(y-x)
=6x^2y(x-y)-2xy^2(x-y)-8xy(x-y)
=2xy（x-y)(3x-y-4)
(x-y)^2-xy^2+x^2y
=(x-y)^2+x^2y-xy^2
=(x-y)^2+xy(x-y)
=(x-y)(x-y+xy)
答
(2x-3y)^2-(2x+3y)(2x-3y)=(2x-3y)(2x-3y-2x-3y)=-6y(2x-3y)（m+n)^2-4(m-n)^2=(m+n)^2-[2(m-n)]^2 使用平方差公式：得：(3n-m)(3m-n)6x^2y(x-y)-2xy^2(x-y)+8xy(y-x)提出xy（x-y）得：xy（x-y）(6x-2y-8)(x-y)^2-xy...