一道解一元二次不等式的题目.
问题描述:
一道解一元二次不等式的题目.
2x²-7x+6
=2(x²-3.5x)+6
=2(x²-3.5x+3.0625-3.0625)+6
=2(x²-3.5x+3.0625)-6.125+6
=2(x-1.75)²-0.125
答
(x-1.75)²-0.25.
一道解一元二次不等式的题目.
2x²-7x+6
=2(x²-3.5x)+6
=2(x²-3.5x+3.0625-3.0625)+6
=2(x²-3.5x+3.0625)-6.125+6
=2(x-1.75)²-0.125
(x-1.75)²-0.25.