x∧2-3x+2=0如何解?求出x=?
问题描述：
x∧2-3x+2=0如何解?求出x=?
答
x∧2-3x+2=0
(x－1)(x－2)=0
x－1=0或x－2=0
得：x=1或x=2X^3-3X+2=0x^3-x^2+x^2-3x+2=0x^2(x-1)+(x-1)(x-2)=0(x-1)(x^2+x-2)=0(x-1)[(x+1)（x-1）+(x-1)]=0(x-1)（x-1）[(x+1)+1]=0(x-1)^2(x+2)=0x1=x2=1,x3=-2