化简~·cos(2x+π/3)+sinx^2

问题描述:

化简~·cos(2x+π/3)+sinx^2

原式=cos(2x+π/3)+(1-cos2x)/2
=1/2cos2x-√3/2sin2x+1/2-1/2cos2x
=-√3/2sin2x+1/2