已知log以1/2为底(x-3)>1则x的取值范围是

问题描述:

已知log以1/2为底(x-3)>1则x的取值范围是

即log1/2(x-3)>log1/2(1/2)
log1/2(x)递减
所以0log1/2(x-3)>log1/2(1/2)什么意思就是1