(3x^2-2x+1)^2-(3x^2-2x-5)^2
问题描述：
(3x^2-2x+1)^2-(3x^2-2x-5)^2
5/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^3
0.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2
解方程(3x+1)(2u-1)=6(x+2)(y-1)
(X-2)(y-4)=(x-1)(y-1)
答
(3x^2-2x+1)^2-(3x^2-2x-5)^2=[(3x^2-2x+1)-(3x^2-2x-5)][(3x^2-2x+1)+(3x^2-2x-5)]=12(3x^2-2x-2)5/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^3=(5/2)(x-2y)^2n* (x-2y)^n* [2^3(x-2y)^3]=20(x-2y)^(3n+3)(3x+1)(2y-1)=6(x...