已知方程1/4+8(x-1/2008)=1/2,求式子5/2+16(x-1/2008)的值

问题描述:

已知方程1/4+8(x-1/2008)=1/2,求式子5/2+16(x-1/2008)的值
方程要有过程

1/4+8(x-1/2008)=1/2
8(x-1/2008)=1/2-1/4=1/4
16(x-1/2008)=1/2
5/2+16(x-1/2008)
=5/2+1/2
=3