x^4/x^2-1的不定积分怎么算啊?
问题描述:
x^4/x^2-1的不定积分怎么算啊?
答
x^4/(x^2- 1)= 1 +x^2 + (1/2) [ 1/(x-1)- 1/ (x+1) ]
I=x+ x^3 /3 +(1/2) ln| (x-1)/(x+1) | + C